Physics labs burn in hell

[Shadow]

TM:                E^'/E=((-n^2 cosθ+√(n^2-sin^2⁡θ )))/(n^2 cosθ+√(n^2-sin^2⁡θ ))±√(((-4ncosθ)/(n^2 cosθ+√(n^2-sin^2⁡θ )))^2 (Δn)^2+(((2n^2 sinθ(√(n^2-sin^2⁡θ )-cos^2 θ) ))/(n^2 cosθ+√( n^2-sin^2⁡θ ))^2 )^2 (Δθ)^2 )
TE:    E^'/E      =(cosθ-√(n^2-sin^2⁡θ ))/(cosθ+√(n^2-sin^2⁡θ ))±√(((-2ncosθ)/(√(n^2-sin^2⁡θ ) (cosθ+√(n^2-sin^2⁡θ ))^2 ))^2 (Δn)^2+(((2sinθ(cos^2⁡θ/√(n^2-sin^2⁡θ )-√(n^2-sin^2⁡θ )) ))/(cosθ+√(n^2-sin^2⁡θ )))^2 (Δθ)^2 )

[Night Wolf]

*brain fries at overwhelming code*

[Zara_rose_wolf]

8899^)((&&%#6(jd&%35

[prodiGee]

I love fried brains.

[Shadow]

That's the error propagation formula for the reflection coefficients in the Fresnel equations with respect to angle of incidence and index of refraction.

[windhound]

Looks kinda messy, surely there's a meaningful simplification that gives something close

...that, or I hope you get a crib sheet for tests =P

[Shadow]

Haha no I won't be tested on that. That's for error analysis in the labs - one time use only. And yeah, it's pretty ugly, because its just a mess of partial derivitives. I don't want to bother simplifying it anymore, the number of approximations I would have to make just isn't worth it.

[Sabriel]

...just isn't worth it.

Hear, hear. And here it looked SO worthy to me. *sarcasm*

[Night Wolf]

That's the error propagation formula for the reflection coefficients in the Fresnel equations with respect to angle of incidence and index of refraction.

*brain drips out ear*

[Ungatt Trunn II]

And the point of learning this isssss?

[Sabriel]

Yes, the point iiiiiiiiiiiis?

[Ungatt Trunn II]

I await a respone at grid 4567, Bravo Kilo Delta.

[Sabriel]

The response will most likely be indecipherable anyway :P

[Firetooth]

TM:                E^'/E=((-n^2 cosθ+√(n^2-sin^2⁡θ )))/(n^2 cosθ+√(n^2-sin^2⁡θ ))±√(((-4ncosθ)/(n^2 cosθ+√(n^2-sin^2⁡θ )))^2 (Δn)^2+(((2n^2 sinθ(√(n^2-sin^2⁡θ )-cos^2 θ) ))/(n^2 cosθ+√( n^2-sin^2⁡θ ))^2 )^2 (Δθ)^2 )
TE:    E^'/E      =(cosθ-√(n^2-sin^2⁡θ ))/(cosθ+√(n^2-sin^2⁡θ ))±√(((-2ncosθ)/(√(n^2-sin^2⁡θ ) (cosθ+√(n^2-sin^2⁡θ ))^2 ))^2 (Δn)^2+(((2sinθ(cos^2⁡θ/√(n^2-sin^2⁡θ )-√(n^2-sin^2⁡θ )) ))/(cosθ+√(n^2-sin^2⁡θ )))^2 (Δθ)^2 )

Incorrect.

[Sabriel]

Ur face is incorrect.